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November 29, 2015
Posted by **lomas** on Wednesday, October 27, 2010 at 10:31am.

x^2-12x+36-49y2

factored by grouping

x(x-12) (7y-6) (7y+6)

the answer in the book has

(x-6+7y)(x-6-7y)

confused.

- math -
**jai**, Wednesday, October 27, 2010 at 10:40amfirst, notice that the first three terms, x^2-12x+36, is a perfect square, and can be factored into (x-6)(x-6),, now rewriting the expression, it becomes:

(x-6)^2 - 49y^2

(x-6)^2 - (7y)^2

this looks like difference of two squares,, let a = x-6 and b=7y, thus:

a^2 - b^2

(a-b)(a+b)

(x-6-7y)(x-6+7y)

so there,, :)

- math -
**lomas**, Wednesday, October 27, 2010 at 10:42amGotta remember those damn steps. I immediately assumed it was four terms so I factor by grouping. I forgot that you first look for common factor, then squares etc.

Thanks.