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November 23, 2014

November 23, 2014

Posted by **Leanna** on Wednesday, October 27, 2010 at 6:19am.

If the release point is 300 ft above ground, what is the velocity of the ball at the time it hits the ground?

I think you would have to average the feet per seconds but I'm not sure.

- 12th Grade Calculus -
**Ron**, Thursday, October 28, 2010 at 1:54pmUse the physics equation:

Vf^2=Vi^2+2ad where Vi is the initial velocity, a is the acceleration due to gravity or 9.80 m/s^2 and d equals your distance

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