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Posted by jimmy on Wednesday, October 27, 2010 at 4:01am.

the Laplace transform of e^4t(cos 2t)?? please i need help. thanks

first, there is s-shifting here since e^4t is multiplied to cos(2t). from e^4t, we know that a = 4,, and that L{cos 2t} = s/(s^2 + 4) , therefore: L{e^4t(cos 2t)} = (s-a)/((s-a)^2 + 4) = (s-4)/((s-4)^2 + 4) so there,, :)

(3m − 2n)(3m + 4n)

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