Hi, I am doing my lab assignment about Protein Analysis.

Our job is to find the concentration of the casein protein in our original Unknown sample with the initial volume of 2ml.

So after plotting the graph of the data given, we are supposed to find the equation for the line of best fit. I got y= 0.0028x + 0.0338.

We are told to use this equation to determine the protein concentration of our sample remembering that the concentration you determine from our standard curve is based on the diluted volume of 10mls.

To sum it up; for my unknown sample, i know v1=2, v2=10 and absorbance=0.178
I don't know c1, or c2.

How would I determine these two questions:
1. Based on this standard curve, you have determined the protein concentration of your sample to be??

2. Therefore the amount of protein in the original 2ml sample was??

Using my equation of

y= 0.0028x + 0.0338
0.178=0.0028x + 0.0338
(0.178-0.0338)/0.0028 =x
5.15=x

So I got 5.15 for #1...does that seem right? I used the absorbance as y and found x.

Then for #2, I have figured out protein concentration which is also c2, knowing c2,v1,v1; I can then solve for c1 which will give me the amount of protein??
using c1c2=v1v2
I get c1= 2575.

Does this look right?

To determine the protein concentration of your sample and the amount of protein in the original 2ml sample, you'll need to use the equation for the line of best fit, as well as some additional information.

Let's break it down step by step:

1. Calculate the concentration of your sample (c1):
- The equation for the line of best fit is y = 0.0028x + 0.0338.
- Substitute the absorbance value (y) of your sample (0.178) into the equation: 0.178 = 0.0028x + 0.0338.
- Rearrange the equation to solve for x (concentration): 0.0028x = 0.178 - 0.0338.
- Simplify: 0.0028x = 0.1442.
- Divide both sides of the equation by 0.0028 to isolate x: x = 0.1442 / 0.0028.
- Calculate the value of x: x ≈ 51.5.
- This value represents the concentration of your sample (c1).

2. Determine the protein amount in the original 2ml sample:
- Now that you have c1, the concentration of your sample, you can use it to calculate the protein amount in the original 2ml sample (c2).
- Remember that the concentration you determined from the standard curve is based on a diluted volume of 10mls (v2 = 10).
- Use the dilution formula: c1v1 = c2v2.
- Substitute the values into the formula and solve for c2: (51.5)(2) = c2(10).
- Simplify the equation: 103 = 10c2.
- Divide both sides of the equation by 10 to isolate c2: c2 = 103 / 10.
- Calculate the value of c2: c2 = 10.3.
- This value represents the concentration of the protein in the original 2ml sample.

So, in answer to your two questions:

1. The protein concentration of your sample is approximately 51.5 (units depend on the units used in your experiment).

2. The amount of protein in the original 2ml sample is 10.3 units (assuming the units are the same as in the previous step).

Remember to check if your units of measurement are consistent throughout the calculations and match those used in your experiment.