How many liters of a 0.530M sucrose (C12H22O11) solution contain 1.3kg of sucrose?

To find the number of liters of a sucrose solution containing 1.3kg of sucrose, we need to use the formula:

moles = mass / molar mass

First, let's calculate the molar mass of sucrose (C12H22O11):
Molar mass (C) = 12.01 g/mol
Molar mass (H) = 1.008 g/mol
Molar mass (O) = 16.00 g/mol

Molar mass (C12H22O11) = (12.01 * 12) + (1.008 * 22) + (16.00 * 11) = 342.34 g/mol

Next, let's calculate the number of moles of sucrose in 1.3kg:
moles = mass / molar mass = 1300g / 342.34 g/mol ≈ 3.799 moles

Now, let's calculate the volume of the solution in liters:
Molarity (M) = 0.530 M
Volume (V) = moles / Molarity = 3.799 moles / 0.530 M ≈ 7.163 L

Therefore, approximately 7.163 liters of a 0.530M sucrose solution contain 1.3kg of sucrose.

To find the number of liters of a 0.530M sucrose solution that contains 1.3kg of sucrose, we need to use the formula:

Molarity (M) = moles of solute / volume of solution in liters.

First, we need to calculate the moles of sucrose using the given mass:

Mass of sucrose = 1.3kg = 1300g

Now, we can calculate the number of moles of sucrose:

Moles of sucrose = Mass of sucrose / molar mass of sucrose

The molar mass of sucrose (C12H22O11) can be calculated using the atomic masses:

(12g/mol * 12) + (1g/mol * 22) + (16g/mol * 11) = 342g/mol

Moles of sucrose = 1300g / 342g/mol

Now that we have the moles of sucrose, we can use the formula to find the volume of the solution in liters:

Molarity (M) = Moles of sucrose / Volume of solution

0.530M = Moles of sucrose / Volume of solution

Rearranging the formula, we can solve for the volume of the solution:

Volume of solution = Moles of sucrose / Molarity (M)

Substituting in the known values:

Volume of solution = (1300g / 342g/mol) / 0.530M

Volume of solution = 0.9568 mol / 0.530M

Now, we can calculate the volume of the solution in liters:

Volume of solution = 0.9568 mol / 0.530 mol/L

Volume of solution = 1.805 L

Therefore, 1.3kg of sucrose dissolved in a 0.530M sucrose solution would have a volume of 1.805 liters.

Convert 1.3 kg to grams, then to moles. moles = grams/molar mass.

Now that you know how many moles you need, use M = moles/L. You know moles and M, solve for L.