Working on the Amazon River, a biologist isolated DNA from two unknown organisms, P and Q. He discovered that the adenine content of P was 15% and the cytosine content of Q was 42%. This means that:
a) the amount of guanine in P is 15%
b) the amount of guanine and cytosine combined in P is 70%
c) the amount of adenine in Q is 42%
d)the amount of thymine in Q is 21%
e) it takes more enerfy to unwind the DNA of P than the DNA of Q
I think the answer is b, am i correct?
To determine which statement is true, you need to understand the base pairing rules of DNA. In DNA, adenine (A) always pairs with thymine (T) and cytosine (C) always pairs with guanine (G).
Let's analyze the given information:
1. The adenine content of organism P is 15%: This means that the thymine content of P must also be 15% because of the base pairing rule.
2. The cytosine content of organism Q is 42%: This demonstrates that the guanine content of Q is also 42% because of the base pairing rule.
Based on this analysis, we can conclude that the answer is (b) "the amount of guanine and cytosine combined in P is 70%". Since adenine and thymine will make up the remaining 30% of P, the total of guanine and cytosine content in P will be 70% (42% for cytosine + 28% for guanine).