Posted by **joshua** on Tuesday, October 26, 2010 at 10:49am.

A projectile of mass 1.450 kg is shot straight up with an initial speed of 20.0 m/s.

(a) How high would it go if there were no air friction?

(b) If the projectile rises to a maximum height of only 13.9 m, determine the magnitude of the average force due to air resistance.

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**bobpursley**, Tuesday, October 26, 2010 at 11:20am
The initial KEnergy is 1/2 m v^2

The PEnergy at to top must be equal to the initial KEnergy.

mgh=1/2 mv^2 solve for h. Notice m divides out.

b) forceresistance*13.9=1/2 m v^2

solve for the force.

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**B**, Friday, November 5, 2010 at 7:35pm
a) 20.4085

b) 20.8633

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**nt**, Sunday, October 12, 2014 at 9:34am
bob's formula for B) is wrong...

Should be mgh-forceresistance = 1/2 m Vi^2

- physics -
**kobe**, Saturday, August 6, 2016 at 12:55am
nah bruh

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