Monday

November 24, 2014

November 24, 2014

Posted by **joshua** on Tuesday, October 26, 2010 at 10:49am.

(a) How high would it go if there were no air friction?

(b) If the projectile rises to a maximum height of only 13.9 m, determine the magnitude of the average force due to air resistance.

- physics -
**bobpursley**, Tuesday, October 26, 2010 at 11:20amThe initial KEnergy is 1/2 m v^2

The PEnergy at to top must be equal to the initial KEnergy.

mgh=1/2 mv^2 solve for h. Notice m divides out.

b) forceresistance*13.9=1/2 m v^2

solve for the force.

- physics -
**B**, Friday, November 5, 2010 at 7:35pma) 20.4085

b) 20.8633

- physics -
**nt**, Sunday, October 12, 2014 at 9:34ambob's formula for B) is wrong...

Should be mgh-forceresistance = 1/2 m Vi^2

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