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August 28, 2014

August 28, 2014

Posted by **sue** on Monday, October 25, 2010 at 9:00pm.

- algebra -
**jai**, Tuesday, October 26, 2010 at 1:10amwhen you have a term squareroot (for example sqrt(x))in the denominator, multiply it with itself such that the multiplier is equal to one ( sqrt(x)/sqrt(x) ) to remove the squareroot,, in this problem:

1+(-2/(sqroot 5))

1+(-2/(sqroot 5))*(sqrt(5)/sqrt(5))

1+{[-2*sqrt(5)]/5}

therefore:

{[5-2*sqrt(5)]/5}

so there,, :)

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