Posted by Anonymous on Monday, October 25, 2010 at 6:45pm.
Formic acid is a monoprotic acid and KOH is a monohydroxy base; therefore, the reaction is 1:1 as follows:
HCOOH + KOH ==> HCOOK + H2O
So moles HCOOH initially = M x L = ??
moles KOH need to exactly neutralize that HCOOH is the same.
Then M KOH = moles KOH/L KOH
You know M KOH and you know moles KOH, solve for L KOH.
When the reaction is 1:1, you can use the simple formula of
mL HCOOH x M HCOOH = mL KOH x M KOH.
You know three of the four; therefore, you can calculate the fourth. You should get the same answer either way.
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