Posted by Juliet on Monday, October 25, 2010 at 2:49pm.
moles NaOH needed = M x L = ??
moles ASA = same as moles NaOH since this is a 1:1 titration. I assume you know the reaction.
grams ASA = moles ASA x molar mass ASA.
%ASA = (grams ASA/mass sample)*100 = ?
Related Questions
College Chemistry - 1) A 25mL sample of the .265M HCI solution from the previous...
chem - quantitative determination of acetylsalicylic acid in aspirin tablets by ...
Chemistry - An aspirin tablet weighing 0.475 g has been analyzed and contains ...
chemistry - An aspirin tablet weighing 0.475 g has been analyzed and contains 68...
chemistry - An aspirin tablet weighing 0.502 g has been analyzed and contains 68...
chemistry - An aspirin tablet weighing 0.502 g has been analyzed and contains 68...
college chemistry - An aspirin tablet weighing 0.502 g has been analyzed and ...
chemistry - A 0.5130 g aspirin tablet which was dissolved in 95 percent ethanol ...
chemistry - a student dissolves 0.625 g of pure benzoic acid in distilled water ...
chemistry - Mass of Aspirin tablet: 0.357 g 10 mL of 1 M NaOH was added to the ...
For Further Reading