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March 24, 2017

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Find all critical numbers:

2x*sqrt(3x^2+4)?

  • calculus - ,

    is this
    y = 2x*sqrt(3x^2+4) ?

    critical number are
    x and y intercepts, max/min points and points of inflection

    for x-intercept, let y = 0
    for y-intercept , let x = 0

    for max/min , take first derivative, set equal to zero and solve for x. Sub back into original to get the matching y

    for pts. of inflection, set second derivative to zero and solve for x
    sub back into original to get the y

    use product rule to find first derivative.

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