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February 28, 2015

February 28, 2015

Posted by **Zel** on Monday, October 25, 2010 at 1:24pm.

2x*sqrt(3x^2+4)?

- calculus -
**Reiny**, Monday, October 25, 2010 at 3:13pmis this

y = 2x*sqrt(3x^2+4) ?

critical number are

x and y intercepts, max/min points and points of inflection

for x-intercept, let y = 0

for y-intercept , let x = 0

for max/min , take first derivative, set equal to zero and solve for x. Sub back into original to get the matching y

for pts. of inflection, set second derivative to zero and solve for x

sub back into original to get the y

use product rule to find first derivative.

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