Post a New Question


posted by on .

Metal Specific Heat (J/g-C)
Al (s) 0.900
Au(s) 0.129
Cu(s) 0.385
Fe(s) 0.444
Hg(l) 0.139
H2O(l) 4.184
C2H5OH(l) 2.46

Using the above table, determine the final temperature if 713.6J is released from a 48.2g sample of copper initially at 93.8o C.

i keep coming up withthe wrong answer for this
i am getting 1822.111
i am getting 1822.111
but when i punch it back into the equation its wrong
please help

  • chemistry - ,

    I don't get 1822.11 no matter how I do it. First, are you using 28.2 g for the metal? The problem states 48.2 g
    -713.6 = 48.2*0.385(Tf-93.8) and I get something like 55.3 C. If I check that number, I get this.
    q = mass x sp. h. x (Tf-Ti)
    q = 48.2 x 0.385 x (55.3-93.8)
    q = 48.2 x 0.385 x (-38.5)
    q = -714.4 (the small difference is caused by rounding the final T to three s.f. My calculator reads 55.345 and that rounds to 55.3 to 3 s.f. If I used 55.345 I get
    q = 48.2*0.385*(55.345-93.8)
    q = 48.2*0.385*(-38.455) = -713.61 which is very close.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question