Posted by **christine** on Monday, October 25, 2010 at 1:13pm.

Metal Specific Heat (J/g-C)

Al (s) 0.900

Au(s) 0.129

Cu(s) 0.385

Fe(s) 0.444

Hg(l) 0.139

H2O(l) 4.184

C2H5OH(l) 2.46

Using the above table, determine the final temperature if 713.6J is released from a 48.2g sample of copper initially at 93.8o C.

i keep coming up withthe wrong answer for this

i am getting 1822.111

-713.6=28.2(.385)(Tf-93.8)

i am getting 1822.111

but when i punch it back into the equation its wrong

please help

- chemistry -
**DrBob222**, Monday, October 25, 2010 at 1:56pm
I don't get 1822.11 no matter how I do it. First, are you using 28.2 g for the metal? The problem states 48.2 g

-713.6 = 48.2*0.385(Tf-93.8) and I get something like 55.3 C. If I check that number, I get this.

q = mass x sp. h. x (Tf-Ti)

q = 48.2 x 0.385 x (55.3-93.8)

q = 48.2 x 0.385 x (-38.5)

q = -714.4 (the small difference is caused by rounding the final T to three s.f. My calculator reads 55.345 and that rounds to 55.3 to 3 s.f. If I used 55.345 I get

q = 48.2*0.385*(55.345-93.8)

q = 48.2*0.385*(-38.455) = -713.61 which is very close.

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