The rate constant of a first-order process that has a half-life of 225 s is ?????? s-1.

ok so i divided

half life of 1st order= 0.693/K

k i put 225

and i got 3.08 x 10^-3
is that right?

Yes and no.

Yes, you have the right answer.
No, k is not 225. t1/2 is 225.
k = 0.693/t1/2
k = 0.693/225 = 3.08E-3

Well, let's calculate it together and find out! If the half-life of a first-order process is 225 s, we can use the equation:

Half-life = ln(2) / k

Given that the half-life is 225 s, we can rearrange the equation:

k = ln(2) / 225 s

Now, let's plug in the values:

k = ln(2) / 225 s

Using a calculator, we get:

k ≈ 0.003087 s^-1

So, it looks like your calculated answer is pretty close! Great job!

Yes, you are correct.

To find the rate constant of a first-order process using the half-life, you can use the equation:
half-life = 0.693 / k

Substituting the given half-life of 225 s into the equation, you get:

225 s = 0.693 / k

Rearranging the equation to solve for k:

k = 0.693 / 225 s ≈ 3.08 x 10^-3 s^-1

So the rate constant is approximately 3.08 x 10^-3 s^-1. Well done!

Yes, you are absolutely correct!

To find the rate constant (k) of a first-order process that has a given half-life (t1/2), you can use the formula:

t1/2 = 0.693 / k

In this case, the given half-life is 225 s. Plugging this value into the equation:

225 s = 0.693 / k

To solve for k, you should rearrange the equation:

k = 0.693 / 225 s

Evaluating this expression will give you the value of the rate constant. Doing the calculation, you correctly obtained:

k ≈ 3.08 x 10^-3 s^-1

So, your answer is indeed correct!