I'm in 5th grade pls. help.
Amanda has a collection of X, Y and Z. Every X is a Y. One half the Z's are Y's. There are 3 times as many Y's as X's. Amanda has 50 Z's and 40 X's. No Z is an X. How many Y's does Amanda have that are neither X's nor Z's?
To find out how many Y's Amanda has that are neither X's nor Z's, we need to use the given information and logic.
Let's break down the information given:
1. Every X is a Y.
2. One half the Z's are Y's.
3. There are 3 times as many Y's as X's.
4. Amanda has 50 Z's and 40 X's.
5. No Z is an X.
From the given information, we can deduce the following:
First, let's calculate the number of Y's:
Since every X is a Y, and Amanda has 40 X's, there are also 40 Y's.
Next, let's calculate the number of Z's that are Y's:
Since one half of the Z's are Y's, and Amanda has 50 Z's, there are 50 / 2 = 25 Y's that are also Z's.
Now, let's find out the number of Y's that are neither X's nor Z's:
Since there are 40 X's and 25 Y's that are Z's, we subtract those from the total number of Y's to get the remaining Y's that are neither X's nor Z's:
40 Y's (X's) + 25 Y's (Z's) = 65 Y's
Total Y's = 65
Therefore, Amanda has a total of 65 Y's that are neither X's nor Z's.