Posted by Fred on Monday, October 25, 2010 at 11:21am.
let the truck' distance from the intersection be x miles
make a diagram and you should have a right-angles triangle with sides x,1, and let the hypotenuse be y
given dx/dt = 60 mph
find dy/dt when x = 3
y^2 = x^2 + 1
2y dy/dt = 2x dx/dt
dy/dt = (x dx/dt)/y
when x = 3, y = √10
dy/dt = 3(60)/√10 = appr. 56.92 mph
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