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November 27, 2014

November 27, 2014

Posted by **Fred** on Monday, October 25, 2010 at 11:21am.

- Calculus -
**Reiny**, Monday, October 25, 2010 at 11:40amlet the truck' distance from the intersection be x miles

make a diagram and you should have a right-angles triangle with sides x,1, and let the hypotenuse be y

given dx/dt = 60 mph

find dy/dt when x = 3

y^2 = x^2 + 1

2y dy/dt = 2x dx/dt

dy/dt = (x dx/dt)/y

when x = 3, y = √10

dy/dt = 3(60)/√10 = appr. 56.92 mph

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