posted by alex on .
In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 3.9 m/s at an angle of 13.8° below the horizontal. It is released 0.65 m above the floor. What horizontal distance does the ball cover before bouncing?
it's initial vertical downward speed is 3.9sin13.8
h=.65 -3.9sin13.8*t-4.9t^2=0 solve for t
then, horizontal distance=3.9cos13.8*t
How high is the ball when it hits the wall?
How long does it take for the ball to reach the wall if it is 5.2 m away?