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March 30, 2017

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A car reaches a speed of 40m/s from rest in a time of 8 seconds. After the 8 seconds, the car travels at a constant velocity fro 200meters when it runs out of gas. The car slowly comes to rest 30 seconds after running out of gas.

Calculate acceleration for the first 8 seconds

  • Physics - ,

    acceleration is change in velocity over time, or:
    a = (v2 - v1)/t
    where v1 = 0, v2 = 40 m/s and t = 8 s
    therefore:
    a = (40 - 0)/8
    a = 5 m/(s^2)

    so there,, :)

  • Physics - ,

    Thanks to jai for the correct answer. This is another question that contains a lot of irrelevant information for you to choose among. Whatever happens after 8 seconds does not affect the answer.

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