Posted by **Vivek ** on Monday, October 25, 2010 at 12:00am.

A car reaches a speed of 40m/s from rest in a time of 8 seconds. After the 8 seconds, the car travels at a constant velocity fro 200meters when it runs out of gas. The car slowly comes to rest 30 seconds after running out of gas.

Calculate acceleration for the first 8 seconds

- Physics -
**jai**, Monday, October 25, 2010 at 1:19am
acceleration is change in velocity over time, or:

a = (v2 - v1)/t

where v1 = 0, v2 = 40 m/s and t = 8 s

therefore:

a = (40 - 0)/8

a = 5 m/(s^2)

so there,, :)

- Physics -
**drwls **, Monday, October 25, 2010 at 8:17am
Thanks to jai for the correct answer. This is another question that contains a lot of irrelevant information for you to choose among. Whatever happens after 8 seconds does not affect the answer.

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