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December 21, 2014

December 21, 2014

Posted by **CMM** on Sunday, October 24, 2010 at 11:17pm.

I am not sure how to take the 2nd derivative?

f'(x)= sec x tan x

f"(x)=???

Is it f"(x)= (sec x tan x)(sec^2x)???

Please Help!

- Calc -
**Reiny**, Sunday, October 24, 2010 at 11:24pmf'(x)= sec x tan x is correct

now use the product rule

f''(x) = secx(sec^2x) + tanx(secx)(tanx)

= sec^3 x + secx(tan^2x)

I will leave the subbing to you

- Calc -
**Chelsea**, Monday, October 25, 2010 at 1:55amWhat do you mean subbing? I thought that was the final answer? In the book it leaves f"(x)= - cos x for f(x)= cos x

- Calc -
**Chelsea**, Monday, October 25, 2010 at 2:08amOops, sorry about that. Do you mean this:

sec^3(Pi/4) + sec(Pi/4)(tan^2(Pi/4)) =

3*sqrt(2)

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