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March 2, 2015

March 2, 2015

Posted by **christine** on Sunday, October 24, 2010 at 8:53pm.

please help

thanks

Metal Specific Heat (J/g-C)

Al (s) 0.900

Au(s) 0.129

Cu(s) 0.385

Fe(s) 0.444

Hg(l) 0.139

H2O(l) 4.184

C2H5OH(l) 2.46

A piece of metal at a temp of 95.0oC and a mass of 67.0 g is dropped into a beaker of water containing 100 g at a temp. of 30.0oC. If the final temperature reached is 42.7.0oC, what is the identity of the metal?

the sum of the heats gained is zero.

heatgainedmetal+heatgainedwater=0

95*cm*(30-95)=100*4.18(42.7-30)

1.28

would it be Au?

- chemistry -
**DrBob222**, Sunday, October 24, 2010 at 10:40pmI don't think so.

I think the 95 you have listed should be 67 g (at least from the post) and delta T for the metal is (Tfinal-Tintial). The final T from the problem is 42.7 and the initial is 95 isn't it? Check your numbers in the post. That may be a typo.

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