Posted by **Steve smith** on Sunday, October 24, 2010 at 7:32pm.

A boy standing on top of a hill throws a stone horizontally. The stone hits the ground at the foot of the hill 2.5 s later. How high is the hill ?

- physics -
**MathMate**, Sunday, October 24, 2010 at 9:13pm
The rock was thrown horizontally, so u, the initial vertical velocity = 0

Use equations of motion:

u = initial vertical velocity = 0

S = vertical distance travelled, m

t = time, s

g = acceleration due to gravity, 9.81 m/s²

S = ut + (1/2)at²

Solve for S.

- physics -
**ho**, Tuesday, December 16, 2014 at 10:33am
v1y = 0

a = -9.8 m/s

t = 2.5s

d = ?

d = v1t + 1/2(a)(t)^2

d = 0 + 1/2 (-9.8)(2.5)^2

d = -30.625

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