Physics
posted by Eden on .
Now assume that the pitcher in Part D throws a 0.145kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of 8.4 N*s to the baseball?

Balls cannot travel in a straight line, if gravity is present.
impulse= changeelocity*mass
8.4=.145(32V)
solve for V 
The equation here is 8.4=.145(32+V)