Posted by **Eden** on Sunday, October 24, 2010 at 5:07pm.

Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of -8.4 N*s to the baseball?

- Physics -
**bobpursley**, Sunday, October 24, 2010 at 5:10pm
Balls cannot travel in a straight line, if gravity is present.

impulse= changeelocity*mass

-8.4=.145(-32-V)

solve for V

- Physics -
**David**, Saturday, November 30, 2013 at 6:18pm
The equation here is -8.4=.145(-32+V)

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