Yep its me again... sorry for re-posting this question but I am quite desperate here and I need to have this question answered, sorry if that sounds rude.

IF 2.0 J of work is done raising g apple how far is it lifted?

I know W= Fd

hence I divided instead of multiplying and I got this: 0.11 which does not sound right. In the book makes a reference saying an apple from your waist to the top of your head is about 1J but not sure that can help.

I would appreciate any help.

I have no idea what you mean by "g apple". The distance it is lifted is

H= Work/(M*g)

One needs to know the apple's mass M in order to answer the question.

Perhaps they told you what M was, but you didn't tell us.

I'm sorry if that sounds rude.

Sorry typo I meant 180 g apple, I am really sorry

No problem, I'm here to help! Let's break down the problem and solve it step by step.

The equation for work is W = Fd, where W is the work done, F is the force applied, and d is the distance moved.

In this case, we are given that 2.0 J of work is done raising an apple. So, W = 2.0 J.

We need to find the distance lifted, which is represented by d.

The force applied (F) is not given, but we know that the only force acting on the apple is the gravitational force (weight). The weight of an object is given by the equation W = mg, where m is the mass of the object and g is the acceleration due to gravity.

Let's assume the mass of the apple is 0.1 kg (you can change this value if needed). The acceleration due to gravity is approximately 9.8 m/s².

So, the weight (force applied) of the apple would be:
F = mg = (0.1 kg) * (9.8 m/s²) = 0.98 N

Now, we can solve for the distance (d) using the formula W = Fd:
2.0 J = (0.98 N) * d

To get the value of d, we need to rearrange the equation:
d = 2.0 J / 0.98 N

Now, let's calculate:
d ≈ 2.04 m

So, the apple is lifted approximately 2.04 meters.

I hope this helps! Let me know if you have any further questions.