Posted by **sally** on Sunday, October 24, 2010 at 4:17pm.

A mechanic pushes a 3.6 multiplied by 103 kg car from rest to a speed of v, doing 4600 J of work in the process. During this time, the car moves 27.0 m. Neglecting friction between car and road, find each of the following.

(a) the speed v

m/s

(b) the horizontal force exerted on the car

N

- Physics -
**drwls **, Sunday, October 24, 2010 at 4:36pm
(a) The final kinetic energy,

(M/2)(Vfinal)^2,

is the work done.

(b) Since the work done is also

F*X = F*27.0 m,

you can solve for the horizontal force, F.

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