November 25, 2015

Homework Help: calculus

Posted by CMM on Sunday, October 24, 2010 at 3:51pm.

Find the points on the curve y= (cos x)/(2 + sin x) at which the tangent is horizontal.

I am not sure, but would I find the derivative first:

y'= [(2 + sin x)(-sin x) - (cos x)(cos x)]/(2 + sin x)^2

But then I don't know what to do or if that is even correct???

Would I simplify: (-sin x)*(sin x + 2) - (cos x)^2*(sin x + 2)^2

Then I would plug points in (x,y), but I am not given points.

Please Help!

Answer this Question

First Name:
School Subject:

Related Questions

More Related Questions