physics
posted by Lauren on .
A hockey puck sliding on a frozen lake comes to rest after traveling 265 m.
If its initial velocity is 4.2 m/s, what is its acceleration (assumed constant)?
Answer in units of m/s2.

Vf^2 = Vo^2 + 2ad,
0^2 = (4.2)^2 + 2 * a * d,
0 = 17.64 + 530a,
530a = 17.64,
a = 17.64 / 530 = 0.0333 m/s^2. 
A hockey puck sliding on a frozen lake comes
to rest after traveling 302 m.
If its initial velocity is 2.9 m/s, what is its
acceleration (assumed constant)?
Answer in units of m/s
2
.