Posted by Jennifer on Sunday, October 24, 2010 at 1:30pm.
A stone is tied to a string (length = 0.450 m) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string is nearly parallel to the ground. Next, the circle is vertical. In the vertical case the maximum tension in the string is 18.0% larger than the tension that exists when the circle is horizontal. Determine the speed of the stone.

Physics  bobpursley, Sunday, October 24, 2010 at 1:33pm
in the vertical, tension at the bottom is mg+mv^2/r
In the horizontal, tension is mv^2/r
1.18 mv^2/r=mg+mv^2/r
solve for v

Physics  Jennifer, Sunday, October 24, 2010 at 1:44pm
How do u know the mass?

Physics  bobpursley, Sunday, October 24, 2010 at 1:47pm
Mass does not matter. Notice mass divides out. divide both sides of the equation by m.

Physics  Adam, Sunday, October 24, 2010 at 1:49pm
What did u you get as the answer.. i have a feeling mine is wrong

Physics  Adam, Sunday, October 24, 2010 at 1:59pm
I can't divide out the v's and I know you are solving for "v".. but I can't seem to finish it out..
I got...
8.1v^2=mg+mv^2/r Then
8.1v^2=g + v^2/.45
then I don't know what to do from there
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