Posted by Anonymous on .
given that the energy released per fissin of Uranium235 nucleus is 200Mev, calculate the number of fissions and amount of energy available if 50g of Uranium235 is completely fissioned

science 
drwls,
50 g of U235 is 50/235 = 0.2128 moles.
Multiply that by Avogadro's number for the number of atoms.
200 MeV = 200*10^6 eV*1.602*10^19 J/eV
= 3.2*10^11 J
E = 0.2128 moles*6.02^10^23 atoms/mole*3.2*10^11 J/atom =