Ca3(PO4)2 + 2H2SO4 = 2CASO4 + Ca(H2PO4)2
How many moles of CaSO4 can be produced by the reaction of 0.39 moles of Ca3(PO4)2 with excess H2 SO4?
Happ face !!
To find out how many moles of CaSO4 can be produced, we need to use the stoichiometry of the balanced equation. The balanced equation is:
Ca3(PO4)2 + 2H2SO4 → 2CaSO4 + Ca(H2PO4)2
From the balanced equation, we can see that 1 mole of Ca3(PO4)2 produces 2 moles of CaSO4. Therefore, we can set up a proportion to find the number of moles of CaSO4 produced:
(0.39 moles Ca3(PO4)2) / (1 mole Ca3(PO4)2) = (x moles CaSO4) / (2 moles CaSO4)
Simplifying the proportion:
0.39 / 1 = x / 2
Cross-multiplying:
0.39 * 2 = x
x = 0.78 moles
Therefore, 0.78 moles of CaSO4 can be produced by the reaction of 0.39 moles of Ca3(PO4)2 with excess H2SO4.