for the reaction: c3h8+5o2=3co2 +4h2o how many moles of o2 will be produced in the complete combustion of 0.75 moles of c3h8?
To solve this problem, we first need to determine the stoichiometry of the reaction, which relates the amount of reactants and products in a chemical reaction. The balanced equation for the combustion of propane (C3H8) is:
C3H8 + 5O2 = 3CO2 + 4H2O
According to this balanced equation, for every one mole of C3H8, we need 5 moles of O2 to form 3 moles of CO2 and 4 moles of H2O.
We are given that the amount of C3H8 is 0.75 moles. Based on the stoichiometry, we can set up a ratio:
0.75 moles C3H8 : X moles O2
Using the balanced equation, the ratio of C3H8 to O2 is 1:5, so we can set up the proportion:
0.75 moles C3H8 / 1 * X moles O2 / 5 = 1
Simplifying the proportion, we get:
0.75X = 5
Solving for X, we divide both sides by 0.75:
X = 5 / 0.75
X ≈ 6.67 moles
Therefore, in the complete combustion of 0.75 moles of C3H8, approximately 6.67 moles of O2 will be produced.