Posted by **aok19** on Saturday, October 23, 2010 at 4:38pm.

Object 1 has a mass m1 and a velocity vector v 1 = (2.87 m/s)xhat. Object 2 has a mass m2 and a velocity vector v 2 = (3.06 m/s)yhat. The total momentum of these two objects has a magnitude of 18.6 kg · m/s and points in a direction 66.5° above the positive x-axis. Find m1 and m2.

- physics -
**bobpursley**, Saturday, October 23, 2010 at 4:41pm
Momentum is a vector:

18.6@66.5 deg= M1*2.87i + M2*3.06j

18.6cos66.5 i + 18.6sin66.5j=...

18.6cos66.5=M1*2.87 solve for M1

18.6 sin66.5=M2*2.87 solve for M2

- physics -
**Ace**, Monday, November 29, 2010 at 7:35pm
Bob got it pretty much right

P=total momentum

theta=angle

Pcos(theta)=m1*v1

Psin(theta)=m2*v2

for M2 bob accidentally said v1 for v2

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