Find a number whose square root is 24 more than 5 times the number.

How do I set up this problem?

let the number be x

√x = 5x+24
square both sides
x = 25x^2 + 240x + 576
25x^2 + 239 + 576 = 0

If you use the formula on this quadratic you will see that it has no real solution.

To set up this problem, let's represent the number as "x". We are looking for a number whose square root is 24 more than 5 times the number. In mathematical terms, this can be written as:

√x = 5x + 24

So, the equation we need to solve is the square root of x equals 5x plus 24. Now we can proceed to solve for x.