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August 30, 2014

August 30, 2014

Posted by **Anonymous** on Saturday, October 23, 2010 at 12:24pm.

I do not seem to get the answer... I find the first derivative of f(x0 and equate it to the value of the slope from the tangent line. the answer says it should be (4,3) but i do not even get the x-value correct.

- Math - point on the graph (check +help) -
**Reiny**, Saturday, October 23, 2010 at 1:33pmmy derivatiave is (1/2)(2x+1)^(-1/2)(2)

= 1/√(2x+1) , that is the slope of the tangent.

slope of 3x+y+4 = -3

so the slope of the perpendicular is 1/3

then 1/√(2x+1) = 1/3

square both sides and crossmultiply

2x+1 = 9

x = 4

sub x=4 into original to finish

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