Posted by **Anonymous** on Saturday, October 23, 2010 at 12:24pm.

Determine the coordinates of the point on the graph of f(x)=sqrt(2x+1) where the tangent line is perpendicular to the line 3x+y+4=0

I do not seem to get the answer... I find the first derivative of f(x0 and equate it to the value of the slope from the tangent line. the answer says it should be (4,3) but i do not even get the x-value correct.

## Answer this Question

## Related Questions

- Math - point on the graph - Determine the coordinates of the point on the graph ...
- Math--Calculus - Let y = f(x) be the continuous function that satisfies the ...
- calculus - Determine the coordinates of the point on the graph of f(x)= (2x+1)^(...
- Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...
- Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...
- Math- calculus - Given f(x) = x ^ 3 - x ^ 2 -4x +4 Find the zeros of f. Write an...
- calculus - let f be the function f(x) = x^3 + 3x^2 - x + 2 a. the tangent to the...
- Calculus - 1. Given the function f defined by f(x) = x^3-x^2-4X+4 a. Find the ...
- College Math - 2008 (2nd)Course2-4.1 We are to find a function f(x) such that ...
- math - The line y=2x + b is tangent to the graph y= sqrt x at the point P= (a,...

More Related Questions