Tuesday

September 30, 2014

September 30, 2014

Posted by **Anonymous** on Saturday, October 23, 2010 at 12:24pm.

I do not seem to get the answer... I find the first derivative of f(x0 and equate it to the value of the slope from the tangent line. the answer says it should be (4,3) but i do not even get the x-value correct.

- Math - point on the graph (check +help) -
**Reiny**, Saturday, October 23, 2010 at 1:33pmmy derivatiave is (1/2)(2x+1)^(-1/2)(2)

= 1/√(2x+1) , that is the slope of the tangent.

slope of 3x+y+4 = -3

so the slope of the perpendicular is 1/3

then 1/√(2x+1) = 1/3

square both sides and crossmultiply

2x+1 = 9

x = 4

sub x=4 into original to finish

**Answer this Question**

**Related Questions**

Math - point on the graph - Determine the coordinates of the point on the graph ...

Math--Calculus - Let y = f(x) be the continuous function that satisfies the ...

calculus - Determine the coordinates of the point on the graph of f(x)= (2x+1)^(...

Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...

Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...

Math- calculus - Given f(x) = x ^ 3 - x ^ 2 -4x +4 Find the zeros of f. Write an...

calculus - let f be the function f(x) = x^3 + 3x^2 - x + 2 a. the tangent to the...

Calculus - 1. Given the function f defined by f(x) = x^3-x^2-4X+4 a. Find the ...

College Math - 2008 (2nd)Course2-4.1 We are to find a function f(x) such that ...

math - The line y=2x + b is tangent to the graph y= sqrt x at the point P= (a,...