Post a New Question

Algebra II

posted by on .

Jack usually mows his lawn in 6 hours. Marilyn can mow the same lawn in 7 hours. How long would it take if they were both working together?

  • Algebra II - ,

    Jack's rate = lawn/6
    Marilyn's rate = lawn/7
    combined rate = lawn/6 + lawn/7 = 13lawn/42

    combined time = lawn/(13lawn/42) = 42/13 or 3.23 hours

    it would take about 2 hours and 14 minutes.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question