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November 29, 2014

November 29, 2014

Posted by **jj reddick** on Friday, October 22, 2010 at 8:48pm.

- trig -
**Reiny**, Friday, October 22, 2010 at 10:53pmmake triangles for each case , then use Pythagoras

if sinx = 1/5, then cosx = √24/5

if cosy = 2/3 , the siny = √5/3

sin(x+y) = sinxcosy + cosxsiny

= (1/5)(2/3) + (√24/5)(√5/3)

= (2 + √120)/15

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