An object with a mass of 2.489x10^1 kg is subjected to a force of 4.8124x10^2 N directed at an angle of 2.819x10^1 degrees from the x axis. A second force of 2.84529x10^3 N acting in the negative X directions is also applied to the object. To two significant figures what is the net acceleration in the X direction?

see the other post in the y direction.

To find the net acceleration in the X direction, we need to calculate the x-component of each force. We can then sum up the x-components to find the net acceleration.

First, let's find the x-component of the force at an angle:

F_x = F * cos(theta)

where F is the magnitude of the force and theta is the angle with respect to the x-axis.

Plugging in the values given:

F_x = 4.8124x10^2 N * cos(2.819x10^1 degrees)

Now, let's find the x-component of the second force:

F2_x = -2.84529x10^3 N (negative because it is in the negative X direction)

Now we can find the net acceleration:

Net acceleration in the x-direction = (Sum of x-components of forces) / mass

Net acceleration = (F_x + F2_x) / mass

Substituting the values we calculated:

Net acceleration = (4.8124x10^2 N * cos(2.819x10^1 degrees) - 2.84529x10^3 N) / (2.489x10^1 kg)

Calculating this expression will give us the net acceleration in the X direction.