It takes the elevator in a skyscraper 4.0 to reach its cruising speed of 10 . A 60 passenger gets aboard on the ground floor.What is the passenger's apparent weight while the elevator is speeding up?

How can any question be answered with units are ignored?

apparentweight= ma+ma

To find the passenger's apparent weight while the elevator is speeding up, we need to consider the concept of apparent weight and the forces acting on the passenger.

When an elevator accelerates upward, there are two forces acting on the passenger: the gravitational force (weight) and the normal force exerted by the floor of the elevator. The apparent weight is the net force experienced by the passenger.

To calculate the apparent weight, we need to use Newton's second law:

Net force = mass x acceleration

First, let's convert the given values to the appropriate units:
- Cruising speed: 10 m/s
- Time to reach cruising speed: 4.0 s
- Passenger count: 60 passengers

Now, let's proceed with the calculations step by step:

Step 1: Calculate the acceleration of the elevator.
Since we know the time it takes for the elevator to reach its cruising speed, we can use the following kinematic equation:
Acceleration = change in velocity / time taken
Acceleration = 10 m/s / 4.0 s
Acceleration = 2.5 m/s²

Step 2: Calculate the force exerted by the elevator floor on the passenger.
The force exerted by the elevator floor on the passenger is equal to the apparent weight. We can calculate it using the following equation:
Force = mass x acceleration

However, we currently have the passenger count instead of the mass of a single passenger. To find the mass of a single passenger, we'll need additional information such as the average weight of a passenger. Could you please provide that information?