How many moles of NF3 are in 850.49 grams of nitrogen triflouride

NF3? how many moles of NF3 are in 850.49grams?

molesNF3=mass/molmassNF3

921.4919096 g/mol

does this look to be right?

or 1 grams 850.49 NF3 is equal to 0.00108519672238 mole does this look better?

No, it doesn't look right to me.

molar mass NF3 = 71.00
So 850.49/71.00 = ??
I don't know how you came up with 921 something for a molar mass.

To determine the number of moles of NF3 in a given mass of nitrogen trifluoride (NF3), you need to use the molar mass of NF3. The molar mass is the mass of one mole of a substance and is calculated by summing the atomic masses of its constituent elements.

Let's begin by finding the molar mass of NF3:

Nitrogen (N) atomic mass = 14.007 grams/mole
Fluorine (F) atomic mass = 18.998 grams/mole (one mole of F atoms since there are three in NF3)

Molar mass of NF3 = (1 * Nitrogen atomic mass) + (3 * Fluorine atomic mass)
= (1 * 14.007) + (3 * 18.998)
= 14.007 + 56.994
= 70.001 grams/mole

Now that we have the molar mass of NF3, we can use it to find the number of moles in 850.49 grams of NF3.

Number of moles = Mass in grams / Molar mass
= 850.49 g / 70.001 g/mol

Dividing 850.49 grams by 70.001 grams/mole will give you the number of moles of NF3 in the given mass.

Calculating this division gives:
Number of moles = 12.15 moles

Therefore, there are approximately 12.15 moles of NF3 in 850.49 grams of nitrogen trifluoride.