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October 1, 2014

October 1, 2014

Posted by **ckim** on Friday, October 22, 2010 at 3:48am.

someone please help me?!

- algebra -
**jai**, Friday, October 22, 2010 at 5:13amrepresent the unknowns using variables:

let x = shortest piece

let y = 2nd longest piece

let (x+y) - 6 = longest piece *according to the 2nd statement*

set up equations:

(1) x + y + (x+y) - 6 = 58

*total length must be 58*

(2) 5x = y + (x+y) - 6 - 10

*according to 3rd statement*

these equations are simplified to:

(1) y = 32 - x

(2) y = 2x + 8

we then substitute the first equation to the second, o that everything will be in terms of x,, or you can do the other way around:

32 - x = 2x + 8

-3x = -24

x = 8 cm [length of shortest]

*using the simplifies equation (1), we get y:

y = 32-x = 24 cm [length of 2nd longest]

(x+y)-6 = 26 cm [length of longest]

**to check, see if their sum is equal to 58 cm,,

so there,, :)

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