The pH of water collected in a stormwater run-off downstream from a Union Carbide chemical factory is 4.82. Calculate the H+ ion concentration of rainwater.

The problem may start with:
pH= -log H+ = 4.82. The answer is 1.5x10 power -5. Again, Can you please show steps for maths.

pH =-log(H^+)

4.82 = -log(H^+)
log(H^+) = -4.82
Take the antilog of both sides.
The antilog of log (H^+) is, or course, just (H^+). To find the antilog of -4.82, punch that number into your calculator and hit the 10x button. It should return 1.51 x 10-5

To calculate the H+ ion concentration of rainwater given the pH value, we can use the formula:

[H+] = 10^(-pH)

In this case, the pH value is given as 4.82. Plugging this value into the formula, we get:

[H+] = 10^(-4.82)

Now, to calculate this mathematically, we need to understand the concept of exponents and logarithms. The formula for the logarithm of a number is:

log N = x

This means that 10^x = N, where N is the number we want to find the logarithm of.

In this case, we want to find 10^(-4.82), which is the inverse of the logarithm. To calculate this, we can use the scientific notation.

10^(-4.82) = 1.5 * 10^(-5)

So, the H+ ion concentration of the rainwater is 1.5 x 10^(-5).