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April 16, 2014

April 16, 2014

Posted by **brian** on Thursday, October 21, 2010 at 11:18pm.

- algebra -
**Henry**, Saturday, October 23, 2010 at 9:49pmIn order to catchup, train B must travel the same distance; but its' time must be 1/2 hour less:

Train A time = t hrs,

Train B time = (t - 0.5) hrs.

d2 = d1,

84(t - 0.5) = 80t,

84t - 42 = 80t,

84t - 80t = 42,

4t = 42,

t = 42/4 = 10.5 hrs,

(t - 0.5) = 10.5 - 0.5 =10h to catchup.

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