posted by Louise on .
how do you write an equation of the line containing point (4,-3) and perpendicular to the line y=3x-5? show steps please
you should have come across the property that the slopes of perpendicular lines are "negative reciprocals" of each other.
slope of y = 3x+ 5 is 3
so the slope of new line is -1/3
new equation: y = (-1/3)x + b
sub in the point(4,-3) to find b
replace b in the new equation and you are done.