# algebra help

posted by on .

Two motorcyclists start at the same point and travel in opposite directions. One travel 3 mph faster than the other. In two hours they are 206 miles apart. How fast is each traveling?

The speed of the slower motorcyclist is ___ mph.

• algebra help - ,

speed of slower ---- x mph
speed of faster ---- x+3 mph

after 2 hours:
distance covered by slower = 2x
distance covered by faster = 2(x+3)

solve
2x + 2(x+3) = 206
.
.

• algebra help - ,

• algebra help - ,

You tell me .

Does that answer work for the original conditions?

• algebra help - ,

i think so but the answer suppose to be in the form of x and y

• algebra help - ,

Are you looking at the answers to this question?
There is no need for two variables

I defined x to be the slower speed, and x = 50
I defined x+3 to be the faster speed, or x+3 = 53

distance covered by slower in 2 hours = 2(50) = 100 miles
distance covered by faster in 2 hours = 2(53) = 106
and what is 100+106 ? ...
looks good to me.

• algebra help - ,

206

• algebra help - ,

so what is the speed of the slower biker ?

• algebra help - ,

53

• algebra help - ,

good!