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September 21, 2014

September 21, 2014

Posted by **Anonymous** on Thursday, October 21, 2010 at 8:42pm.

- algebra -
**Reiny**, Thursday, October 21, 2010 at 9:03pmtime for faster train --- t hours

time for slower train === t + 1.5

distance of faster train = 60t

distance of slower train = 40(t+1.5)

but the distances are the same .....

can you take it from there.

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