A sports car accelerates from rest to 89 km/h in 6.1s . What is its average acceleration in
average acceleration in m/s squared
Vo=0km/h
V1=89 km/h
t0=0
t1=6.1
89-0/6.1-0=14.5 km/hr (Round to 2 sig figs=15 km/hr) You then have to convert km/hr to m/s^2.
15km/hr * 1000m/3600s= 4.1m/s^2
3600s = 1hr
*hope that helps
To find the average acceleration, you need to use the formula:
Average acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 km/h (since the car starts from rest)
Final velocity (v) = 89 km/h
Time (t) = 6.1 s
First, convert the velocities from km/h to m/s:
Initial velocity (u) = 0 km/h = 0 m/s
Final velocity (v) = 89 km/h = (89 x 1000) / 3600 = 24.7 m/s
Now, substitute the values into the formula:
Average acceleration = (24.7 m/s - 0 m/s) / 6.1 s
Average acceleration = 24.7 m/s / 6.1 s
Average acceleration ≈ 4.05 m/s²
Therefore, the average acceleration of the sports car is approximately 4.05 m/s².