Posted by Jay on Thursday, October 21, 2010 at 5:58pm.
%H2O = (12*molar mass H2O/molar mass KAl(SO)4)2.12H2O)*100 = ??
% anhydrous alum = 100 - %H2O
fraction anydrous alum = % anhydrous alum/100.
grams anhydrous alum in 100 g alum = 100g x fraction anhydrous alum.
By the way, there is no water, theoretical or otherwise, in anhydrous alum.
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