posted by Sarah on .
Problem#9: Consider the fuel octane (the main component of gasoline) and its combustion reaction
2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l)
ΔHo = -10,942 kJ
The “fuel value” of a fuel (unit kJ/g) is defined as the energy released when 1 g of the fuel undergoes combustion. Calculate the fuel value of octane. (MM of C8H18 = 114 g/mol)
Convert 1 g of octane to moles. Then multiply that by (1/2)*10,942 kJ, becasuse the reaction as written consumes 2 moles of octane.