solve tis 5x^+4x+1+3(1-3x)

To solve the equation 5x^2 + 4x + 1 + 3(1 - 3x), you can follow these steps:

Step 1: Simplify the equation by applying the distributive property:
5x^2 + 4x + 1 + 3 - 9x

Step 2: Combine like terms:
5x^2 - 5x + 4

Now, we have a quadratic equation in the form of ax^2 + bx + c, where a = 5, b = -5, and c = 4.

To find the solutions, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values:
x = (-(-5) ± √((-5)^2 - 4(5)(4))) / (2(5))
x = (5 ± √(25 - 80)) / 10
x = (5 ± √(-55)) / 10

Since the discriminant (b^2 - 4ac) is negative in this case, we can conclude that the equation has no real solutions.