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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Thursday, October 21, 2010 at 12:28pm.

- calculus -
**drwls**, Thursday, October 21, 2010 at 1:38pmThey will be the same when the number of years x (measured from mid-2007) satisfies the following equation:

1.132*(1.016)^x = 1.318*1.006)^x

1.1643 = (1.016/1.006)^x = 1.0099^x

Use logs to solve. I get 15.5 years, making it late 2022 or early 2023.

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