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August 20, 2014

August 20, 2014

Posted by **Anonymous** on Thursday, October 21, 2010 at 11:13am.

- calculus -
**Reiny**, Thursday, October 21, 2010 at 11:24amsolve for t

1132 e^(.016t) = 1318 e^(.06t)

That will give you the time when they are equal.

You will have to use logs. (use ln)

- Typo - calculus -
**Reiny**, Thursday, October 21, 2010 at 11:34amJust noticed you have a typo, and I read it as .06

does it say 0.6 % ?

if so change my equation to

1132 e^(.016t) = 1318 e^(.006t)

You should get a t value of 15.2, add that to the year 2007 and draw your conclusion from that.

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