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July 30, 2014

July 30, 2014

Posted by **Dave** on Thursday, October 21, 2010 at 9:08am.

x^3-4xy^2/3x^3-2x^2y-8xy^2

- Math -
**jai**, Thursday, October 21, 2010 at 9:44amfactor out x in numerator and denominator to cancel,, it then becomes:

(x^2-4y^2)/(3x^2-2xy-8y^2)

factor both numerator and denominator:

[(x-2y)(x+2y)]/[(x-2y)(3x+4y)]

cancel (x-2y), therefore:

(x+2y)/(3x+4y)

so there,, :)

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